A bipolar transistor can be made to approximate an ideal switch.
Consider a common emitter transistor circuit,
A collector resistance RC is connected from the transistor collector to the supply voltage VCC.
The emitter terminal of the device is grounded.
For the transistor to simulate a switch, the terminals of the switch are the transistor collector and emitter.
The input voltage or the controlling voltage for the transistor switch is the base-emitter voltage VBE.
The collector-emitter voltage VCE is equal to the supply voltage minus the voltage drop across RC,
When the transistor base-emitter voltage is zero or reverse biased, the base current IB is zero, and the collector current IC is also zero. The transistor switch is now in its OFF condition.
Since there is no collector current, there can be no voltage drop across the load resistor.
Therefore when IC=0,
Thus, when an ideal transistor switch is OFF, its collector-emitter voltage equals the supply voltage.
When the transistor base is made positive with respect to the emitter, a base current IB flows. The collector current IC is equal to IB multiplied by the transistor common-emitter dc current gain hFE.
i.e. IC=hFE*IB
If IB is made large enough, ICRC can become equal to the supply voltage VCC.
Therefore,
Thus, when an ideal transistor switch is ON, its collector-emitter voltage equals zero.
Ideally, it dissipates zero power when ON or OFF.
Transistor power dissipation is given by,
Consider a common emitter transistor circuit,
A collector resistance RC is connected from the transistor collector to the supply voltage VCC.
The emitter terminal of the device is grounded.
For the transistor to simulate a switch, the terminals of the switch are the transistor collector and emitter.
The input voltage or the controlling voltage for the transistor switch is the base-emitter voltage VBE.
The collector-emitter voltage VCE is equal to the supply voltage minus the voltage drop across RC,
VCE=VCC-ICRC
When the transistor base-emitter voltage is zero or reverse biased, the base current IB is zero, and the collector current IC is also zero. The transistor switch is now in its OFF condition.
Since there is no collector current, there can be no voltage drop across the load resistor.
Therefore when IC=0,
VCE=VCC
When the transistor base is made positive with respect to the emitter, a base current IB flows. The collector current IC is equal to IB multiplied by the transistor common-emitter dc current gain hFE.
i.e. IC=hFE*IB
If IB is made large enough, ICRC can become equal to the supply voltage VCC.
VCE=VCC-VCC=0
Ideally, it dissipates zero power when ON or OFF.
Transistor power dissipation is given by,
PD=ICVCE
When the switch is OFF, IC=0,
PD=0
When the switch is ON, VCE=0,
PD=0
The only time power is dissipated is when the device is switching between ON and OFF.